Base | Representation |
---|---|
bin | 10001101000000111000… |
… | …111100100001110111010 |
3 | 11021210120121000211010022 |
4 | 101220013013210032322 |
5 | 124321220322421102 |
6 | 2324244051050442 |
7 | 153341101554434 |
oct | 21500707441672 |
9 | 4253517024108 |
10 | 1211300201402 |
11 | 427789426715 |
12 | 176911ba0a22 |
13 | 8a2c0780a05 |
14 | 428ad221654 |
15 | 21796cc85a2 |
hex | 11a071e43ba |
1211300201402 has 4 divisors (see below), whose sum is σ = 1816950302106. Its totient is φ = 605650100700.
The previous prime is 1211300201351. The next prime is 1211300201431. The reversal of 1211300201402 is 2041020031121.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1137718756321 + 73581445081 = 1066639^2 + 271259^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 302825050349 + ... + 302825050352.
Almost surely, 21211300201402 is an apocalyptic number.
1211300201402 is a deficient number, since it is larger than the sum of its proper divisors (605650100704).
1211300201402 is an equidigital number, since it uses as much as digits as its factorization.
1211300201402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 605650100703.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 1211300201402 its reverse (2041020031121), we get a palindrome (3252320232523).
The spelling of 1211300201402 in words is "one trillion, two hundred eleven billion, three hundred million, two hundred one thousand, four hundred two".
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