121130023117 has 2 divisors, whose sum is σ = 121130023118. Its totient is φ = 121130023116.

The previous prime is 121130023099. The next prime is 121130023123. The reversal of 121130023117 is 711320031121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 70448307241 + 50681715876 = 265421^2 + 225126^2 .

It is a cyclic number.

It is not a de Polignac number, because 121130023117 - 2¹⁵ = 121129990349 is a prime.

It is a super-3 number, since 3×121130023117³ (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121130023717) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60565011558 + 60565011559.

It is an arithmetic number, because the mean of its divisors is an integer number (60565011559).

Almost surely, 2^121130023117 is an apocalyptic number.

It is an amenable number.

121130023117 is a deficient number, since it is larger than the sum of its proper divisors (1).

121130023117 is an equidigital number, since it uses as much as digits as its factorization.

121130023117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252, while the sum is 22.

Adding to 121130023117 its reverse (711320031121), we get a palindrome (832450054238).

The spelling of 121130023117 in words is "one hundred twenty-one billion, one hundred thirty million, twenty-three thousand, one hundred seventeen".