1211300333130 has 16 divisors (see below), whose sum is σ = 2907120799584. Its totient is φ = 323013422160.

The previous prime is 1211300333129. The next prime is 1211300333149. The reversal of 1211300333130 is 313330031121.

It is a junction number, because it is equal to n+sod(n) for n = 1211300333097 and 1211300333106.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20188338856 + ... + 20188338915.

It is an arithmetic number, because the mean of its divisors is an integer number (181695049974).

Almost surely, 2^{1211300333130} is an apocalyptic number.

1211300333130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1211300333130 is an abundant number, since it is smaller than the sum of its proper divisors (1695820466454).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1211300333130 is a wasteful number, since it uses less digits than its factorization.

1211300333130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40376677781.

The product of its (nonzero) digits is 486, while the sum is 21.

Adding to 1211300333130 its reverse (313330031121), we get a palindrome (1524630364251).

The spelling of 1211300333130 in words is "one trillion, two hundred eleven billion, three hundred million, three hundred thirty-three thousand, one hundred thirty".