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121130098191581 is a prime number
BaseRepresentation
bin11011100010101011001100…
…011110010110110011011101
3120212212220221210220100120112
4123202223030132112303131
5111334043420114112311
61105342222055055405
734341234516261323
oct3342531436266335
9525786853810515
10121130098191581
1135660a93634aa6
12117039a8971565
135278699a2965b
1421caa29a21d13
15e00d1267928b
hex6e2acc796cdd

121130098191581 has 2 divisors, whose sum is σ = 121130098191582. Its totient is φ = 121130098191580.

The previous prime is 121130098191577. The next prime is 121130098191757. The reversal of 121130098191581 is 185191890031121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111584680123225 + 9545418068356 = 10563365^2 + 3089566^2 .

It is a cyclic number.

It is not a de Polignac number, because 121130098191581 - 22 = 121130098191577 is a prime.

It is a super-2 number, since 2×1211300981915812 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121130098101581) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60565049095790 + 60565049095791.

It is an arithmetic number, because the mean of its divisors is an integer number (60565049095791).

Almost surely, 2121130098191581 is an apocalyptic number.

It is an amenable number.

121130098191581 is a deficient number, since it is larger than the sum of its proper divisors (1).

121130098191581 is an equidigital number, since it uses as much as digits as its factorization.

121130098191581 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 155520, while the sum is 50.

The spelling of 121130098191581 in words is "one hundred twenty-one trillion, one hundred thirty billion, ninety-eight million, one hundred ninety-one thousand, five hundred eighty-one".