121131002143 has 2 divisors, whose sum is σ = 121131002144. Its totient is φ = 121131002142.

The previous prime is 121131002131. The next prime is 121131002149. The reversal of 121131002143 is 341200131121.

It is a strong prime.

It is an emirp because it is prime and its reverse (341200131121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 121131002143 - 2²¹ = 121128904991 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 121131002143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121131002149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60565501071 + 60565501072.

It is an arithmetic number, because the mean of its divisors is an integer number (60565501072).

Almost surely, 2^121131002143 is an apocalyptic number.

121131002143 is a deficient number, since it is larger than the sum of its proper divisors (1).

121131002143 is an equidigital number, since it uses as much as digits as its factorization.

121131002143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 121131002143 its reverse (341200131121), we get a palindrome (462331133264).

The spelling of 121131002143 in words is "one hundred twenty-one billion, one hundred thirty-one million, two thousand, one hundred forty-three".