Search a number
-
+
121131013001 is a prime number
BaseRepresentation
bin111000011001111111…
…0001001001110001001
3102120122211101000122212
41300303332021032021
53441034014404001
6131351413554505
711515511423255
oct1606376111611
9376584330585
10121131013001
114740a331a09
121b586645a35
13b56560612b
145c11639265
15323e4157bb
hex1c33f89389

121131013001 has 2 divisors, whose sum is σ = 121131013002. Its totient is φ = 121131013000.

The previous prime is 121131012967. The next prime is 121131013037. The reversal of 121131013001 is 100310131121.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 60676005625 + 60455007376 = 246325^2 + 245876^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121131013001 is a prime.

It is not a weakly prime, because it can be changed into another prime (121131013051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60565506500 + 60565506501.

It is an arithmetic number, because the mean of its divisors is an integer number (60565506501).

Almost surely, 2121131013001 is an apocalyptic number.

It is an amenable number.

121131013001 is a deficient number, since it is larger than the sum of its proper divisors (1).

121131013001 is an equidigital number, since it uses as much as digits as its factorization.

121131013001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 121131013001 its reverse (100310131121), we get a palindrome (221441144122).

The spelling of 121131013001 in words is "one hundred twenty-one billion, one hundred thirty-one million, thirteen thousand, one".