Base | Representation |
---|---|
bin | 111000011001111111… |
… | …0100110000011111011 |
3 | 102120122211121000201001 |
4 | 1300303332212003323 |
5 | 3441034032144011 |
6 | 131351420305431 |
7 | 11515512424543 |
oct | 1606376460373 |
9 | 376584530631 |
10 | 121131131131 |
11 | 4740a40273a |
12 | 1b5866a2277 |
13 | b565647b2a |
14 | 5c1166a323 |
15 | 323e43a7c1 |
hex | 1c33fa60fb |
121131131131 has 2 divisors, whose sum is σ = 121131131132. Its totient is φ = 121131131130.
The previous prime is 121131131117. The next prime is 121131131159. The reversal of 121131131131 is 131131131121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 121131131131 - 29 = 121131130619 is a prime.
It is a super-2 number, since 2×1211311311312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 121131131099 and 121131131108.
It is not a weakly prime, because it can be changed into another prime (121131131831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60565565565 + 60565565566.
It is an arithmetic number, because the mean of its divisors is an integer number (60565565566).
Almost surely, 2121131131131 is an apocalyptic number.
121131131131 is a deficient number, since it is larger than the sum of its proper divisors (1).
121131131131 is an equidigital number, since it uses as much as digits as its factorization.
121131131131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 54, while the sum is 19.
Adding to 121131131131 its reverse (131131131121), we get a palindrome (252262262252).
It can be divided in two parts, 121 and 131131131, that multiplied together give a palindrome (15866866851).
The spelling of 121131131131 in words is "one hundred twenty-one billion, one hundred thirty-one million, one hundred thirty-one thousand, one hundred thirty-one".
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