Base | Representation |
---|---|
bin | 111000011001111111… |
… | …0100110000011101101 |
3 | 102120122211121000200112 |
4 | 1300303332212003231 |
5 | 3441034032143432 |
6 | 131351420305405 |
7 | 11515512424523 |
oct | 1606376460355 |
9 | 376584530615 |
10 | 121131131117 |
11 | 4740a402727 |
12 | 1b5866a2265 |
13 | b565647b19 |
14 | 5c1166a313 |
15 | 323e43a7b2 |
hex | 1c33fa60ed |
121131131117 has 2 divisors, whose sum is σ = 121131131118. Its totient is φ = 121131131116.
The previous prime is 121131131089. The next prime is 121131131131. The reversal of 121131131117 is 711131131121.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 64055054281 + 57076076836 = 253091^2 + 238906^2 .
It is a cyclic number.
It is not a de Polignac number, because 121131131117 - 210 = 121131130093 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 121131131092 and 121131131101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121131130117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60565565558 + 60565565559.
It is an arithmetic number, because the mean of its divisors is an integer number (60565565559).
Almost surely, 2121131131117 is an apocalyptic number.
It is an amenable number.
121131131117 is a deficient number, since it is larger than the sum of its proper divisors (1).
121131131117 is an equidigital number, since it uses as much as digits as its factorization.
121131131117 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 126, while the sum is 23.
Adding to 121131131117 its reverse (711131131121), we get a palindrome (832262262238).
The spelling of 121131131117 in words is "one hundred twenty-one billion, one hundred thirty-one million, one hundred thirty-one thousand, one hundred seventeen".
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