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1211312143 is a prime number
BaseRepresentation
bin100100000110011…
…0010100000001111
310010102022000212201
41020030302200033
54440043442033
6320110342331
742005661166
oct11014624017
93112260781
101211312143
11571832818
122997ba9a7
13163c55362
14b6c363dd
157152247d
hex4833280f

1211312143 has 2 divisors, whose sum is σ = 1211312144. Its totient is φ = 1211312142.

The previous prime is 1211312131. The next prime is 1211312147. The reversal of 1211312143 is 3412131121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1211312143 - 29 = 1211311631 is a prime.

It is a super-3 number, since 3×12113121433 (a number of 28 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1211312143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1211312147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605656071 + 605656072.

It is an arithmetic number, because the mean of its divisors is an integer number (605656072).

Almost surely, 21211312143 is an apocalyptic number.

1211312143 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211312143 is an equidigital number, since it uses as much as digits as its factorization.

1211312143 is an evil number, because the sum of its binary digits is even.

The product of its digits is 144, while the sum is 19.

The square root of 1211312143 is about 34803.9098809315. The cubic root of 1211312143 is about 1065.9872828828.

Adding to 1211312143 its reverse (3412131121), we get a palindrome (4623443264).

The spelling of 1211312143 in words is "one billion, two hundred eleven million, three hundred twelve thousand, one hundred forty-three".