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12113230331197 is a prime number
BaseRepresentation
bin1011000001000101010011…
…0010100111110100111101
31120220000100211220220111201
42300101110302213310331
53041430343431044242
641432424033015501
72360103065651122
oct260212462476475
946800324826451
1012113230331197
113950212804616
1214377603b4591
1369b371217c68
142dc3d7c04749
1516015d9084b7
hexb0454ca7d3d

12113230331197 has 2 divisors, whose sum is σ = 12113230331198. Its totient is φ = 12113230331196.

The previous prime is 12113230331159. The next prime is 12113230331231. The reversal of 12113230331197 is 79113303231121.

12113230331197 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6453332396281 + 5659897934916 = 2540341^2 + 2379054^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12113230331197 is a prime.

It is a super-2 number, since 2×121132303311972 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12113230331297) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056615165598 + 6056615165599.

It is an arithmetic number, because the mean of its divisors is an integer number (6056615165599).

Almost surely, 212113230331197 is an apocalyptic number.

It is an amenable number.

12113230331197 is a deficient number, since it is larger than the sum of its proper divisors (1).

12113230331197 is an equidigital number, since it uses as much as digits as its factorization.

12113230331197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20412, while the sum is 37.

The spelling of 12113230331197 in words is "twelve trillion, one hundred thirteen billion, two hundred thirty million, three hundred thirty-one thousand, one hundred ninety-seven".