Base | Representation |
---|---|
bin | 111000011010000001… |
… | …1000110011100001101 |
3 | 102120122220211001000021 |
4 | 1300310003012130031 |
5 | 3441034332443313 |
6 | 131351501502141 |
7 | 11515525444354 |
oct | 1606403063415 |
9 | 376586731007 |
10 | 121132312333 |
11 | 4741003a13a |
12 | 1b586b71951 |
13 | b56596c676 |
14 | 5c1189699b |
15 | 323e5c078d |
hex | 1c340c670d |
121132312333 has 4 divisors (see below), whose sum is σ = 121311238140. Its totient is φ = 120953386528.
The previous prime is 121132312307. The next prime is 121132312351. The reversal of 121132312333 is 333213231121.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 333213231121 = 89 ⋅3743968889.
It can be written as a sum of positive squares in 2 ways, for example, as 87071026084 + 34061286249 = 295078^2 + 184557^2 .
It is a cyclic number.
It is not a de Polignac number, because 121132312333 - 213 = 121132304141 is a prime.
It is a super-2 number, since 2×1211323123332 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 121132312298 and 121132312307.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121132312373) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89461888 + ... + 89463241.
It is an arithmetic number, because the mean of its divisors is an integer number (30327809535).
Almost surely, 2121132312333 is an apocalyptic number.
It is an amenable number.
121132312333 is a deficient number, since it is larger than the sum of its proper divisors (178925807).
121132312333 is an equidigital number, since it uses as much as digits as its factorization.
121132312333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 178925806.
The product of its digits is 1944, while the sum is 25.
Adding to 121132312333 its reverse (333213231121), we get a palindrome (454345543454).
The spelling of 121132312333 in words is "one hundred twenty-one billion, one hundred thirty-two million, three hundred twelve thousand, three hundred thirty-three".
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