Base | Representation |
---|---|
bin | 111000011010000001… |
… | …1001000101000110101 |
3 | 102120122220211111100121 |
4 | 1300310003020220311 |
5 | 3441034333240313 |
6 | 131351502011541 |
7 | 11515525512532 |
oct | 1606403105065 |
9 | 376586744317 |
10 | 121132321333 |
11 | 47410045981 |
12 | 1b586b76bb1 |
13 | b5659737aa |
14 | 5c11899d89 |
15 | 323e5c328d |
hex | 1c340c8a35 |
121132321333 has 2 divisors, whose sum is σ = 121132321334. Its totient is φ = 121132321332.
The previous prime is 121132321273. The next prime is 121132321337. The reversal of 121132321333 is 333123231121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 94997719089 + 26134602244 = 308217^2 + 161662^2 .
It is a cyclic number.
It is not a de Polignac number, because 121132321333 - 221 = 121130224181 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 121132321298 and 121132321307.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121132321337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60566160666 + 60566160667.
It is an arithmetic number, because the mean of its divisors is an integer number (60566160667).
Almost surely, 2121132321333 is an apocalyptic number.
It is an amenable number.
121132321333 is a deficient number, since it is larger than the sum of its proper divisors (1).
121132321333 is an equidigital number, since it uses as much as digits as its factorization.
121132321333 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1944, while the sum is 25.
Adding to 121132321333 its reverse (333123231121), we get a palindrome (454255552454).
The spelling of 121132321333 in words is "one hundred twenty-one billion, one hundred thirty-two million, three hundred twenty-one thousand, three hundred thirty-three".
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