Base | Representation |
---|---|
bin | 10110100100000001… |
… | …00111010100011011 |
3 | 1011021012022221211021 |
4 | 23102000213110123 |
5 | 144302001423003 |
6 | 5321554143311 |
7 | 606115305343 |
oct | 132200472433 |
9 | 34235287737 |
10 | 12113311003 |
11 | 5156714932 |
12 | 2420881b37 |
13 | 11b0788c61 |
14 | 82cab5d23 |
15 | 4ad6a42bd |
hex | 2d202751b |
12113311003 has 2 divisors, whose sum is σ = 12113311004. Its totient is φ = 12113311002.
The previous prime is 12113310949. The next prime is 12113311057. The reversal of 12113311003 is 30011331121.
It is a balanced prime because it is at equal distance from previous prime (12113310949) and next prime (12113311057).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12113311003 is a prime.
It is not a weakly prime, because it can be changed into another prime (12113318003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056655501 + 6056655502.
It is an arithmetic number, because the mean of its divisors is an integer number (6056655502).
Almost surely, 212113311003 is an apocalyptic number.
12113311003 is a deficient number, since it is larger than the sum of its proper divisors (1).
12113311003 is an equidigital number, since it uses as much as digits as its factorization.
12113311003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 12113311003 its reverse (30011331121), we get a palindrome (42124642124).
The spelling of 12113311003 in words is "twelve billion, one hundred thirteen million, three hundred eleven thousand, three".
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