Base | Representation |
---|---|
bin | 111000011010000011… |
… | …0011111111101110001 |
3 | 102120122222111022012112 |
4 | 1300310012133331301 |
5 | 3441040100001223 |
6 | 131351532535105 |
7 | 11515536145103 |
oct | 1606406377561 |
9 | 376588438175 |
10 | 121133203313 |
11 | 47410598591 |
12 | 1b587321495 |
13 | b565bc2085 |
14 | 5c11a49573 |
15 | 323e6e9778 |
hex | 1c3419ff71 |
121133203313 has 2 divisors, whose sum is σ = 121133203314. Its totient is φ = 121133203312.
The previous prime is 121133203309. The next prime is 121133203337. The reversal of 121133203313 is 313302331121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 120841750129 + 291453184 = 347623^2 + 17072^2 .
It is a cyclic number.
It is not a de Polignac number, because 121133203313 - 22 = 121133203309 is a prime.
It is a super-4 number, since 4×1211332033134 (a number of 45 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (121133233313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60566601656 + 60566601657.
It is an arithmetic number, because the mean of its divisors is an integer number (60566601657).
Almost surely, 2121133203313 is an apocalyptic number.
It is an amenable number.
121133203313 is a deficient number, since it is larger than the sum of its proper divisors (1).
121133203313 is an equidigital number, since it uses as much as digits as its factorization.
121133203313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 121133203313 its reverse (313302331121), we get a palindrome (434435534434).
The spelling of 121133203313 in words is "one hundred twenty-one billion, one hundred thirty-three million, two hundred three thousand, three hundred thirteen".
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