Base | Representation |
---|---|
bin | 1011000001000101101011… |
… | …0110101000001010000111 |
3 | 1120220000121221022110211020 |
4 | 2300101122312220022013 |
5 | 3041431101000410143 |
6 | 41432442105042223 |
7 | 2360105442340131 |
oct | 260213266501207 |
9 | 46800557273736 |
10 | 12113332044423 |
11 | 3950265166235 |
12 | 143778a486373 |
13 | 69b38930b4bc |
14 | 2dc407520051 |
15 | 1601677ea883 |
hex | b045ada8287 |
12113332044423 has 8 divisors (see below), whose sum is σ = 16415881677936. Its totient is φ = 7943168553600.
The previous prime is 12113332044377. The next prime is 12113332044491. The reversal of 12113332044423 is 32444023331121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12113332044423 - 213 = 12113332036231 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12113332044493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 33096535458 + ... + 33096535823.
It is an arithmetic number, because the mean of its divisors is an integer number (2051985209742).
Almost surely, 212113332044423 is an apocalyptic number.
12113332044423 is a deficient number, since it is larger than the sum of its proper divisors (4302549633513).
12113332044423 is an equidigital number, since it uses as much as digits as its factorization.
12113332044423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66193071345.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 12113332044423 its reverse (32444023331121), we get a palindrome (44557355375544).
The spelling of 12113332044423 in words is "twelve trillion, one hundred thirteen billion, three hundred thirty-two million, forty-four thousand, four hundred twenty-three".
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