Base | Representation |
---|---|
bin | 10001101000001001011… |
… | …111011001000000100000 |
3 | 11021210200100220212100001 |
4 | 101220021133121000200 |
5 | 124321311020020222 |
6 | 2324252032105344 |
7 | 153342064060240 |
oct | 21501137310040 |
9 | 4253610825301 |
10 | 1211340001312 |
11 | 4277a993aa01 |
12 | 176923395254 |
13 | 8a2c8aa745c |
14 | 428b4621b20 |
15 | 2179a53ae27 |
hex | 11a097d9020 |
1211340001312 has 48 divisors (see below), whose sum is σ = 2725816750272. Its totient is φ = 519088239360.
The previous prime is 1211340001217. The next prime is 1211340001327. The reversal of 1211340001312 is 2131000431121.
It is a self number, because there is not a number n which added to its sum of digits gives 1211340001312.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1759987 + ... + 2349517.
It is an arithmetic number, because the mean of its divisors is an integer number (56787848964).
Almost surely, 21211340001312 is an apocalyptic number.
It is an amenable number.
1211340001312 is an abundant number, since it is smaller than the sum of its proper divisors (1514476748960).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1211340001312 is an equidigital number, since it uses as much as digits as its factorization.
1211340001312 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 598721 (or 598713 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1211340001312 its reverse (2131000431121), we get a palindrome (3342340432433).
The spelling of 1211340001312 in words is "one trillion, two hundred eleven billion, three hundred forty million, one thousand, three hundred twelve".
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