121134000241 has 2 divisors, whose sum is σ = 121134000242. Its totient is φ = 121134000240.

The previous prime is 121134000199. The next prime is 121134000283. The reversal of 121134000241 is 142000431121.

It is a balanced prime because it is at equal distance from previous prime (121134000199) and next prime (121134000283).

It can be written as a sum of positive squares in only one way, i.e., 117154913841 + 3979086400 = 342279^2 + 63080^2 .

It is an emirp because it is prime and its reverse (142000431121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 121134000241 - 2²¹ = 121131903089 is a prime.

It is not a weakly prime, because it can be changed into another prime (121137000241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60567000120 + 60567000121.

It is an arithmetic number, because the mean of its divisors is an integer number (60567000121).

Almost surely, 2^121134000241 is an apocalyptic number.

It is an amenable number.

121134000241 is a deficient number, since it is larger than the sum of its proper divisors (1).

121134000241 is an equidigital number, since it uses as much as digits as its factorization.

121134000241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 121134000241 its reverse (142000431121), we get a palindrome (263134431362).

The spelling of 121134000241 in words is "one hundred twenty-one billion, one hundred thirty-four million, two hundred forty-one", and thus it is an aban number.