Base | Representation |
---|---|
bin | 10001101000001001011… |
… | …111110110010000010110 |
3 | 11021210200101010221200000 |
4 | 101220021133312100112 |
5 | 124321311032333420 |
6 | 2324252034432130 |
7 | 153342065066430 |
oct | 21501137662026 |
9 | 4253611127600 |
10 | 1211340121110 |
11 | 4277a9a11a09 |
12 | 176923432646 |
13 | 8a2c8b19b42 |
14 | 428b4653650 |
15 | 2179a561690 |
hex | 11a097f6416 |
1211340121110 has 192 divisors, whose sum is σ = 3734797248000. Its totient is φ = 276723827712.
The previous prime is 1211340121073. The next prime is 1211340121129. The reversal of 1211340121110 is 111210431121.
1211340121110 is a `hidden beast` number, since 1 + 211 + 340 + 1 + 2 + 1 + 110 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 32113041 + ... + 32150739.
It is an arithmetic number, because the mean of its divisors is an integer number (19452069000).
Almost surely, 21211340121110 is an apocalyptic number.
1211340121110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 1211340121110, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1867398624000).
1211340121110 is an abundant number, since it is smaller than the sum of its proper divisors (2523457126890).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1211340121110 is a wasteful number, since it uses less digits than its factorization.
1211340121110 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 39617 (or 39605 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 18.
Adding to 1211340121110 its reverse (111210431121), we get a palindrome (1322550552231).
It can be divided in two parts, 1211 and 340121110, that added together give a triangular number (340122321 = T26081).
The spelling of 1211340121110 in words is "one trillion, two hundred eleven billion, three hundred forty million, one hundred twenty-one thousand, one hundred ten".
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