1211342430031 has 2 divisors, whose sum is σ = 1211342430032. Its totient is φ = 1211342430030.

The previous prime is 1211342430013. The next prime is 1211342430043. The reversal of 1211342430031 is 1300342431121.

Together with previous prime (1211342430013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1211342430031 - 2¹⁹ = 1211341905743 is a prime.

It is a super-2 number, since 2×1211342430031² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1211342429978 and 1211342430005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1211342430131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605671215015 + 605671215016.

It is an arithmetic number, because the mean of its divisors is an integer number (605671215016).

Almost surely, 2^{1211342430031} is an apocalyptic number.

1211342430031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211342430031 is an equidigital number, since it uses as much as digits as its factorization.

1211342430031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1211342430031 its reverse (1300342431121), we get a palindrome (2511684861152).

The spelling of 1211342430031 in words is "one trillion, two hundred eleven billion, three hundred forty-two million, four hundred thirty thousand, thirty-one".