Base | Representation |
---|---|
bin | 10110100100000010… |
… | …00110111010010011 |
3 | 1011021012120112022212 |
4 | 23102001012322103 |
5 | 144302020043103 |
6 | 5322001022335 |
7 | 606116354531 |
oct | 132201067223 |
9 | 34235515285 |
10 | 12113440403 |
11 | 51567a3079 |
12 | 24209249ab |
13 | 11b0802b1c |
14 | 82cb0b151 |
15 | 4ad6cc7d8 |
hex | 2d2046e93 |
12113440403 has 2 divisors, whose sum is σ = 12113440404. Its totient is φ = 12113440402.
The previous prime is 12113440393. The next prime is 12113440439. The reversal of 12113440403 is 30404431121.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12113440403 is a prime.
It is not a weakly prime, because it can be changed into another prime (12113440463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056720201 + 6056720202.
It is an arithmetic number, because the mean of its divisors is an integer number (6056720202).
Almost surely, 212113440403 is an apocalyptic number.
12113440403 is a deficient number, since it is larger than the sum of its proper divisors (1).
12113440403 is an equidigital number, since it uses as much as digits as its factorization.
12113440403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 12113440403 its reverse (30404431121), we get a palindrome (42517871524).
The spelling of 12113440403 in words is "twelve billion, one hundred thirteen million, four hundred forty thousand, four hundred three".
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