12113444041 has 2 divisors, whose sum is σ = 12113444042. Its totient is φ = 12113444040.

The previous prime is 12113444039. The next prime is 12113444089. The reversal of 12113444041 is 14044431121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10007001225 + 2106442816 = 100035^2 + 45896^2 .

It is a cyclic number.

It is not a de Polignac number, because 12113444041 - 2¹ = 12113444039 is a prime.

Together with 12113444039, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 12113443997 and 12113444015.

It is not a weakly prime, because it can be changed into another prime (12113444341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056722020 + 6056722021.

It is an arithmetic number, because the mean of its divisors is an integer number (6056722021).

Almost surely, 2^12113444041 is an apocalyptic number.

It is an amenable number.

12113444041 is a deficient number, since it is larger than the sum of its proper divisors (1).

12113444041 is an equidigital number, since it uses as much as digits as its factorization.

12113444041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 12113444041 its reverse (14044431121), we get a palindrome (26157875162).

The spelling of 12113444041 in words is "twelve billion, one hundred thirteen million, four hundred forty-four thousand, forty-one".