12113490437136 has 1125 divisors, whose sum is σ = 41857928119645. Its totient is φ = 3381320954880.

The previous prime is 12113490437129. The next prime is 12113490437189. The reversal of 12113490437136 is 63173409431121.

The square root of 12113490437136 is 3480444.

It is a perfect power (a square), and thus also a powerful number.

12113490437136 is a `hidden beast` number, since 1 + 2 + 113 + 4 + 90 + 437 + 13 + 6 = 666.

It can be written as a sum of positive squares in only one way, i.e., 9430918160400 + 2682572276736 = 3070980^2 + 1637856^2 .

It is a junction number, because it is equal to n+sod(n) for n = 12113490437091 and 12113490437100.

It is an unprimeable number.

It is a polite number, since it can be written in 224 ways as a sum of consecutive naturals, for example, 257733839065 + ... + 257733839111.

Almost surely, 2^{12113490437136} is an apocalyptic number.

12113490437136 is a gapful number since it is divisible by the number (16) formed by its first and last digit.

12113490437136 is the 3480444-th square number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12113490437136

12113490437136 is an abundant number, since it is smaller than the sum of its proper divisors (29744437682509).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12113490437136 is an frugal number, since it uses more digits than its factorization.

12113490437136 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 192 (or 80 counting only the distinct ones).

The product of its (nonzero) digits is 326592, while the sum is 45.

Adding to 12113490437136 its reverse (63173409431121), we get a palindrome (75286899868257).

The spelling of 12113490437136 in words is "twelve trillion, one hundred thirteen billion, four hundred ninety million, four hundred thirty-seven thousand, one hundred thirty-six".