121140011000003 has 4 divisors (see below), whose sum is σ = 121341575078808. Its totient is φ = 120938446921200.

The previous prime is 121140010999999. The next prime is 121140011000011. The reversal of 121140011000003 is 300000110041121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 121140011000003 - 2² = 121140010999999 is a prime.

It is a super-3 number, since 3×121140011000003³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (121140011003003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100782038501 + ... + 100782039702.

It is an arithmetic number, because the mean of its divisors is an integer number (30335393769702).

Almost surely, 2^{121140011000003} is an apocalyptic number.

121140011000003 is a deficient number, since it is larger than the sum of its proper divisors (201564078805).

121140011000003 is an equidigital number, since it uses as much as digits as its factorization.

121140011000003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 201564078804.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 121140011000003 its reverse (300000110041121), we get a palindrome (421140121041124).

The spelling of 121140011000003 in words is "one hundred twenty-one trillion, one hundred forty billion, eleven million, three", and thus it is an aban number.