121140041011 has 4 divisors (see below), whose sum is σ = 132152772024. Its totient is φ = 110127310000.

The previous prime is 121140040991. The next prime is 121140041081. The reversal of 121140041011 is 110140041121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 121140041011 - 2⁹ = 121140040499 is a prime.

It is a super-3 number, since 3×121140041011³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (121140041081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5506365490 + ... + 5506365511.

It is an arithmetic number, because the mean of its divisors is an integer number (33038193006).

Almost surely, 2^121140041011 is an apocalyptic number.

121140041011 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

121140041011 is a deficient number, since it is larger than the sum of its proper divisors (11012731013).

121140041011 is a wasteful number, since it uses less digits than its factorization.

121140041011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11012731012.

The product of its (nonzero) digits is 32, while the sum is 16.

Adding to 121140041011 its reverse (110140041121), we get a palindrome (231280082132).

The spelling of 121140041011 in words is "one hundred twenty-one billion, one hundred forty million, forty-one thousand, eleven".