12114012000033 has 6 divisors (see below), whose sum is σ = 17498017333394. Its totient is φ = 8076008000016.

The previous prime is 12114012000019. The next prime is 12114012000049. The reversal of 12114012000033 is 33000021041121.

12114012000033 is a `hidden beast` number, since 1 + 211 + 401 + 20 + 0 + 0 + 0 + 33 = 666.

It can be written as a sum of positive squares in only one way, i.e., 8608549645089 + 3505462354944 = 2934033^2 + 1872288^2 .

It is not a de Polignac number, because 12114012000033 - 2⁵ = 12114012000001 is a prime.

It is a super-3 number, since 3×12114012000033³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12114012000733) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 673000666660 + ... + 673000666677.

Almost surely, 2^{12114012000033} is an apocalyptic number.

It is an amenable number.

12114012000033 is a deficient number, since it is larger than the sum of its proper divisors (5384005333361).

12114012000033 is a wasteful number, since it uses less digits than its factorization.

12114012000033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1346001333343 (or 1346001333340 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 12114012000033 its reverse (33000021041121), we get a palindrome (45114033041154).

The spelling of 12114012000033 in words is "twelve trillion, one hundred fourteen billion, twelve million, thirty-three", and thus it is an aban number.