12114012000733 has 2 divisors, whose sum is σ = 12114012000734. Its totient is φ = 12114012000732.

The previous prime is 12114012000719. The next prime is 12114012000737. The reversal of 12114012000733 is 33700021041121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11059369266969 + 1054642733764 = 3325563^2 + 1026958^2 .

It is a cyclic number.

It is not a de Polignac number, because 12114012000733 - 2²¹ = 12114009903581 is a prime.

It is a super-3 number, since 3×12114012000733³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12114012000698 and 12114012000707.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12114012000737) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6057006000366 + 6057006000367.

It is an arithmetic number, because the mean of its divisors is an integer number (6057006000367).

Almost surely, 2^{12114012000733} is an apocalyptic number.

It is an amenable number.

12114012000733 is a deficient number, since it is larger than the sum of its proper divisors (1).

12114012000733 is an equidigital number, since it uses as much as digits as its factorization.

12114012000733 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 12114012000733 its reverse (33700021041121), we get a palindrome (45814033041854).

The spelling of 12114012000733 in words is "twelve trillion, one hundred fourteen billion, twelve million, seven hundred thirty-three", and thus it is an aban number.