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121140133555 = 573461146673
BaseRepresentation
bin111000011010010000…
…0111011111010110011
3102120200110112101201011
41300310200323322303
53441043333233210
6131352341251351
711515652100640
oct1606440737263
9376613471634
10121140133555
11474144a1361
121b589703b57
13b56747a5cc
145c12930dc7
153240117d8a
hex1c3483beb3

121140133555 has 8 divisors (see below), whose sum is σ = 166135040352. Its totient is φ = 83067520128.

The previous prime is 121140133537. The next prime is 121140133559. The reversal of 121140133555 is 555331041121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 121140133555 - 213 = 121140125363 is a prime.

It is a super-3 number, since 3×1211401335553 (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (121140133559) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1730573302 + ... + 1730573371.

It is an arithmetic number, because the mean of its divisors is an integer number (20766880044).

Almost surely, 2121140133555 is an apocalyptic number.

121140133555 is a deficient number, since it is larger than the sum of its proper divisors (44994906797).

121140133555 is an equidigital number, since it uses as much as digits as its factorization.

121140133555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3461146685.

The product of its (nonzero) digits is 9000, while the sum is 31.

Adding to 121140133555 its reverse (555331041121), we get a palindrome (676471174676).

The spelling of 121140133555 in words is "one hundred twenty-one billion, one hundred forty million, one hundred thirty-three thousand, five hundred fifty-five".

Divisors: 1 5 7 35 3461146673 17305733365 24228026711 121140133555