1211401431283 has 2 divisors, whose sum is σ = 1211401431284. Its totient is φ = 1211401431282.

The previous prime is 1211401431241. The next prime is 1211401431313. The reversal of 1211401431283 is 3821341041121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1211401431283 - 2²⁹ = 1210864560371 is a prime.

It is a super-3 number, since 3×1211401431283³ (a number of 37 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (1211401431203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605700715641 + 605700715642.

It is an arithmetic number, because the mean of its divisors is an integer number (605700715642).

Almost surely, 2^{1211401431283} is an apocalyptic number.

1211401431283 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211401431283 is an equidigital number, since it uses as much as digits as its factorization.

1211401431283 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 31.

The spelling of 1211401431283 in words is "one trillion, two hundred eleven billion, four hundred one million, four hundred thirty-one thousand, two hundred eighty-three".