1211401431313 has 2 divisors, whose sum is σ = 1211401431314. Its totient is φ = 1211401431312.

The previous prime is 1211401431283. The next prime is 1211401431319. The reversal of 1211401431313 is 3131341041121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 944177569344 + 267223861969 = 971688^2 + 516937^2 .

It is a cyclic number.

It is not a de Polignac number, because 1211401431313 - 2¹³ = 1211401423121 is a prime.

It is a super-3 number, since 3×1211401431313³ (a number of 37 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (1211401431319) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605700715656 + 605700715657.

It is an arithmetic number, because the mean of its divisors is an integer number (605700715657).

Almost surely, 2^{1211401431313} is an apocalyptic number.

It is an amenable number.

1211401431313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211401431313 is an equidigital number, since it uses as much as digits as its factorization.

1211401431313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 1211401431313 its reverse (3131341041121), we get a palindrome (4342742472434).

The spelling of 1211401431313 in words is "one trillion, two hundred eleven billion, four hundred one million, four hundred thirty-one thousand, three hundred thirteen".