121140241120159 has 2 divisors, whose sum is σ = 121140241120160. Its totient is φ = 121140241120158.

The previous prime is 121140241120097. The next prime is 121140241120183. The reversal of 121140241120159 is 951021142041121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 121140241120159 - 2¹⁵ = 121140241087391 is a prime.

It is a super-3 number, since 3×121140241120159³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121140241130159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60570120560079 + 60570120560080.

It is an arithmetic number, because the mean of its divisors is an integer number (60570120560080).

Almost surely, 2^{121140241120159} is an apocalyptic number.

121140241120159 is a deficient number, since it is larger than the sum of its proper divisors (1).

121140241120159 is an equidigital number, since it uses as much as digits as its factorization.

121140241120159 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 34.

The spelling of 121140241120159 in words is "one hundred twenty-one trillion, one hundred forty billion, two hundred forty-one million, one hundred twenty thousand, one hundred fifty-nine".