Base | Representation |
---|---|
bin | 10001101000001101010… |
… | …100000100010111110111 |
3 | 11021210211211121112220201 |
4 | 101220031110010113313 |
5 | 124321423430021241 |
6 | 2324302242541331 |
7 | 153343503211444 |
oct | 21501524042767 |
9 | 4253754545821 |
10 | 1211404142071 |
11 | 4278320698a2 |
12 | 176940967847 |
13 | 8a309174076 |
14 | 428bcd5a9cb |
15 | 217a0eaa931 |
hex | 11a0d5045f7 |
1211404142071 has 2 divisors, whose sum is σ = 1211404142072. Its totient is φ = 1211404142070.
The previous prime is 1211404142063. The next prime is 1211404142191. The reversal of 1211404142071 is 1702414041121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1211404142071 - 23 = 1211404142063 is a prime.
It is a super-3 number, since 3×12114041420713 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1211404442071) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605702071035 + 605702071036.
It is an arithmetic number, because the mean of its divisors is an integer number (605702071036).
Almost surely, 21211404142071 is an apocalyptic number.
1211404142071 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211404142071 is an equidigital number, since it uses as much as digits as its factorization.
1211404142071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1792, while the sum is 28.
Adding to 1211404142071 its reverse (1702414041121), we get a palindrome (2913818183192).
The spelling of 1211404142071 in words is "one trillion, two hundred eleven billion, four hundred four million, one hundred forty-two thousand, seventy-one".
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