12114043309 has 2 divisors, whose sum is σ = 12114043310. Its totient is φ = 12114043308.

The previous prime is 12114043301. The next prime is 12114043343. The reversal of 12114043309 is 90334041121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10236987684 + 1877055625 = 101178^2 + 43325^2 .

It is a cyclic number.

It is not a de Polignac number, because 12114043309 - 2³ = 12114043301 is a prime.

It is a super-3 number, since 3×12114043309³ (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12114043301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6057021654 + 6057021655.

It is an arithmetic number, because the mean of its divisors is an integer number (6057021655).

Almost surely, 2^12114043309 is an apocalyptic number.

It is an amenable number.

12114043309 is a deficient number, since it is larger than the sum of its proper divisors (1).

12114043309 is an equidigital number, since it uses as much as digits as its factorization.

12114043309 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 28.

The spelling of 12114043309 in words is "twelve billion, one hundred fourteen million, forty-three thousand, three hundred nine".