121141011113 has 4 divisors (see below), whose sum is σ = 121162295748. Its totient is φ = 121119726480.

The previous prime is 121141011067. The next prime is 121141011119. The reversal of 121141011113 is 311110141121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 16105386649 + 105035624464 = 126907^2 + 324092^2 .

It is a cyclic number.

It is not a de Polignac number, because 121141011113 - 2⁶ = 121141011049 is a prime.

It is a super-3 number, since 3×121141011113³ (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 121141011091 and 121141011100.

It is not an unprimeable number, because it can be changed into a prime (121141011119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10633778 + ... + 10645163.

It is an arithmetic number, because the mean of its divisors is an integer number (30290573937).

Almost surely, 2^121141011113 is an apocalyptic number.

It is an amenable number.

121141011113 is a deficient number, since it is larger than the sum of its proper divisors (21284635).

121141011113 is an equidigital number, since it uses as much as digits as its factorization.

121141011113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21284634.

The product of its (nonzero) digits is 24, while the sum is 17.

Adding to 121141011113 its reverse (311110141121), we get a palindrome (432251152234).

The spelling of 121141011113 in words is "one hundred twenty-one billion, one hundred forty-one million, eleven thousand, one hundred thirteen".