1211411000341 has 4 divisors (see below), whose sum is σ = 1211413608000. Its totient is φ = 1211408392684.

The previous prime is 1211411000321. The next prime is 1211411000363. The reversal of 1211411000341 is 1430001141121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1211411000341 - 2²⁵ = 1211377445909 is a prime.

It is a super-3 number, since 3×1211411000341³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1211411000321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 396541 + ... + 1606258.

It is an arithmetic number, because the mean of its divisors is an integer number (302853402000).

Almost surely, 2^{1211411000341} is an apocalyptic number.

It is an amenable number.

1211411000341 is a deficient number, since it is larger than the sum of its proper divisors (2607659).

1211411000341 is an equidigital number, since it uses as much as digits as its factorization.

1211411000341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2607658.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 1211411000341 its reverse (1430001141121), we get a palindrome (2641412141462).

The spelling of 1211411000341 in words is "one trillion, two hundred eleven billion, four hundred eleven million, three hundred forty-one", and thus it is an aban number.