12114124042113 has 64 divisors (see below), whose sum is σ = 19327330425600. Its totient is φ = 7471141954560.

The previous prime is 12114124042073. The next prime is 12114124042121. The reversal of 12114124042113 is 31124042141121.

12114124042113 is a `hidden beast` number, since 1 + 2 + 1 + 1 + 41 + 2 + 404 + 211 + 3 = 666.

It is not a de Polignac number, because 12114124042113 - 2⁸ = 12114124041857 is a prime.

It is a super-3 number, since 3×12114124042113³ (a number of 40 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is not an unprimeable number, because it can be changed into a prime (12114124042123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 222605695 + ... + 222660107.

It is an arithmetic number, because the mean of its divisors is an integer number (301989537900).

Almost surely, 2^{12114124042113} is an apocalyptic number.

It is an amenable number.

12114124042113 is a deficient number, since it is larger than the sum of its proper divisors (7213206383487).

12114124042113 is a wasteful number, since it uses less digits than its factorization.

12114124042113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62719 (or 62713 counting only the distinct ones).

The product of its (nonzero) digits is 1536, while the sum is 27.

Adding to 12114124042113 its reverse (31124042141121), we get a palindrome (43238166183234).

It can be divided in two parts, 1211412 and 4042113, that added together give a palindrome (5253525).

The spelling of 12114124042113 in words is "twelve trillion, one hundred fourteen billion, one hundred twenty-four million, forty-two thousand, one hundred thirteen".