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1211420204302 = 27117866364963
BaseRepresentation
bin10001101000001110010…
…001010101110100001110
311021210212221211121011011
4101220032101111310032
5124321442033014202
62324304015115434
7153344056560220
oct21501621256416
94253787747134
101211420204302
1142784013a670
12176946212b7a
138a30c5a9049
14428c113c410
15217a25cebd7
hex11a0e455d0e

1211420204302 has 16 divisors (see below), whose sum is σ = 2265513109632. Its totient is φ = 471981897720.

The previous prime is 1211420204279. The next prime is 1211420204327. The reversal of 1211420204302 is 2034020241121.

It is a super-3 number, since 3×12114202043023 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (22).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3933182328 + ... + 3933182635.

It is an arithmetic number, because the mean of its divisors is an integer number (141594569352).

Almost surely, 21211420204302 is an apocalyptic number.

1211420204302 is a deficient number, since it is larger than the sum of its proper divisors (1054092905330).

1211420204302 is a wasteful number, since it uses less digits than its factorization.

1211420204302 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7866364983.

The product of its (nonzero) digits is 768, while the sum is 22.

Adding to 1211420204302 its reverse (2034020241121), we get a palindrome (3245440445423).

The spelling of 1211420204302 in words is "one trillion, two hundred eleven billion, four hundred twenty million, two hundred four thousand, three hundred two".

Divisors: 1 2 7 11 14 22 77 154 7866364963 15732729926 55064554741 86530014593 110129109482 173060029186 605710102151 1211420204302