12114212141 has 2 divisors, whose sum is σ = 12114212142. Its totient is φ = 12114212140.

The previous prime is 12114212107. The next prime is 12114212153. The reversal of 12114212141 is 14121241121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9322674916 + 2791537225 = 96554^2 + 52835^2 .

It is a cyclic number.

It is not a de Polignac number, because 12114212141 - 2¹⁸ = 12113949997 is a prime.

It is a super-3 number, since 3×12114212141³ (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12114212161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6057106070 + 6057106071.

It is an arithmetic number, because the mean of its divisors is an integer number (6057106071).

Almost surely, 2^12114212141 is an apocalyptic number.

It is an amenable number.

12114212141 is a deficient number, since it is larger than the sum of its proper divisors (1).

12114212141 is an equidigital number, since it uses as much as digits as its factorization.

12114212141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 128, while the sum is 20.

Adding to 12114212141 its reverse (14121241121), we get a palindrome (26235453262).

The spelling of 12114212141 in words is "twelve billion, one hundred fourteen million, two hundred twelve thousand, one hundred forty-one".