121142143103140 has 12 divisors (see below), whose sum is σ = 254398500516636. Its totient is φ = 48456857241248.

The previous prime is 121142143103131. The next prime is 121142143103159. The reversal of 121142143103140 is 41301341241121.

It can be written as a sum of positive squares in 2 ways, for example, as 12328370947684 + 108813772155456 = 3511178^2 + 10431384^2 .

It is a super-3 number, since 3×121142143103140³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 121142143103099 and 121142143103108.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3028553577559 + ... + 3028553577598.

It is an arithmetic number, because the mean of its divisors is an integer number (21199875043053).

Almost surely, 2^{121142143103140} is an apocalyptic number.

121142143103140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

121142143103140 is an abundant number, since it is smaller than the sum of its proper divisors (133256357413496).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121142143103140 is a wasteful number, since it uses less digits than its factorization.

121142143103140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6057107155166 (or 6057107155164 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 121142143103140 its reverse (41301341241121), we get a palindrome (162443484344261).

The spelling of 121142143103140 in words is "one hundred twenty-one trillion, one hundred forty-two billion, one hundred forty-three million, one hundred three thousand, one hundred forty".