121142213320133 has 4 divisors (see below), whose sum is σ = 121271500635180. Its totient is φ = 121012926005088.

The previous prime is 121142213320109. The next prime is 121142213320147. The reversal of 121142213320133 is 331023312241121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 18821037775684 + 102321175544449 = 4338322^2 + 10115393^2 .

It is a cyclic number.

It is not a de Polignac number, because 121142213320133 - 2¹⁸ = 121142213057989 is a prime.

It is a super-3 number, since 3×121142213320133³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 121142213320096 and 121142213320105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121142213340133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64643656118 + ... + 64643657991.

It is an arithmetic number, because the mean of its divisors is an integer number (30317875158795).

Almost surely, 2^{121142213320133} is an apocalyptic number.

It is an amenable number.

121142213320133 is a deficient number, since it is larger than the sum of its proper divisors (129287315047).

121142213320133 is an equidigital number, since it uses as much as digits as its factorization.

121142213320133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 129287315046.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 121142213320133 its reverse (331023312241121), we get a palindrome (452165525561254).

The spelling of 121142213320133 in words is "one hundred twenty-one trillion, one hundred forty-two billion, two hundred thirteen million, three hundred twenty thousand, one hundred thirty-three".