12114232041 has 4 divisors (see below), whose sum is σ = 16152309392. Its totient is φ = 8076154692.

The previous prime is 12114232037. The next prime is 12114232051. The reversal of 12114232041 is 14023241121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 12114232041 - 2² = 12114232037 is a prime.

It is a super-3 number, since 3×12114232041³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12114231999 and 12114232017.

It is not an unprimeable number, because it can be changed into a prime (12114232001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2019038671 + ... + 2019038676.

It is an arithmetic number, because the mean of its divisors is an integer number (4038077348).

Almost surely, 2^12114232041 is an apocalyptic number.

It is an amenable number.

12114232041 is a deficient number, since it is larger than the sum of its proper divisors (4038077351).

12114232041 is an equidigital number, since it uses as much as digits as its factorization.

12114232041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4038077350.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 12114232041 its reverse (14023241121), we get a palindrome (26137473162).

The spelling of 12114232041 in words is "twelve billion, one hundred fourteen million, two hundred thirty-two thousand, forty-one".