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1211424340214 = 211471171590271
BaseRepresentation
bin10001101000001110100…
…001000111100011110110
311021210220020121201120002
4101220032201013203312
5124321444112341324
62324304243511302
7153344136664244
oct21501641074366
94253806551502
101211424340214
11427842504a80
12176947688532
138a3103c672a
14428c18d7794
15217a2b4a3ae
hex11a0e8478f6

1211424340214 has 16 divisors (see below), whose sum is σ = 2024507990016. Its totient is φ = 538931524200.

The previous prime is 1211424340211. The next prime is 1211424340267. The reversal of 1211424340214 is 4120434241121.

It is a super-3 number, since 3×12114243402143 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1211424340211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 585794102 + ... + 585796169.

It is an arithmetic number, because the mean of its divisors is an integer number (126531749376).

Almost surely, 21211424340214 is an apocalyptic number.

1211424340214 is a deficient number, since it is larger than the sum of its proper divisors (813083649802).

1211424340214 is a wasteful number, since it uses less digits than its factorization.

1211424340214 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1171590331.

The product of its (nonzero) digits is 6144, while the sum is 29.

Adding to 1211424340214 its reverse (4120434241121), we get a palindrome (5331858581335).

The spelling of 1211424340214 in words is "one trillion, two hundred eleven billion, four hundred twenty-four million, three hundred forty thousand, two hundred fourteen".

Divisors: 1 2 11 22 47 94 517 1034 1171590271 2343180542 12887492981 25774985962 55064742737 110129485474 605712170107 1211424340214