121143101 has 2 divisors, whose sum is σ = 121143102. Its totient is φ = 121143100.

The previous prime is 121143091. The next prime is 121143149. The reversal of 121143101 is 101341121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 86025625 + 35117476 = 9275^2 + 5926^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-121143101 is a prime.

It is a super-3 number, since 3×121143101³ (a number of 25 digits) contains 333 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121143161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60571550 + 60571551.

It is an arithmetic number, because the mean of its divisors is an integer number (60571551).

Almost surely, 2^121143101 is an apocalyptic number.

It is an amenable number.

121143101 is a deficient number, since it is larger than the sum of its proper divisors (1).

121143101 is an equidigital number, since it uses as much as digits as its factorization.

121143101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 14.

The square root of 121143101 is about 11006.5026688772. The cubic root of 121143101 is about 494.8036509968.

Adding to 121143101 its reverse (101341121), we get a palindrome (222484222).

The spelling of 121143101 in words is "one hundred twenty-one million, one hundred forty-three thousand, one hundred one".