Base | Representation |
---|---|
bin | 10110100100001000… |
… | …11011100000010111 |
3 | 1011021021012202211021 |
4 | 23102010123200113 |
5 | 144302230424231 |
6 | 5322031422011 |
7 | 606126642343 |
oct | 132204334027 |
9 | 34237182737 |
10 | 12114311191 |
11 | 5157238334 |
12 | 2421084907 |
13 | 11b0a49298 |
14 | 82cc96623 |
15 | 4ad800811 |
hex | 2d211b817 |
12114311191 has 2 divisors, whose sum is σ = 12114311192. Its totient is φ = 12114311190.
The previous prime is 12114311141. The next prime is 12114311219. The reversal of 12114311191 is 19111341121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12114311191 - 213 = 12114302999 is a prime.
It is a super-3 number, since 3×121143111913 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12114311141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6057155595 + 6057155596.
It is an arithmetic number, because the mean of its divisors is an integer number (6057155596).
Almost surely, 212114311191 is an apocalyptic number.
12114311191 is a deficient number, since it is larger than the sum of its proper divisors (1).
12114311191 is an equidigital number, since it uses as much as digits as its factorization.
12114311191 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 216, while the sum is 25.
The spelling of 12114311191 in words is "twelve billion, one hundred fourteen million, three hundred eleven thousand, one hundred ninety-one".
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