1211431422413 has 4 divisors (see below), whose sum is σ = 1211707316448. Its totient is φ = 1211155528380.

The previous prime is 1211431422373. The next prime is 1211431422433. The reversal of 1211431422413 is 3142241341121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1211431422413 - 2³² = 1207136455117 is a prime.

It is a super-3 number, since 3×1211431422413³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1211431422433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 137940431 + ... + 137949212.

It is an arithmetic number, because the mean of its divisors is an integer number (302926829112).

Almost surely, 2^{1211431422413} is an apocalyptic number.

It is an amenable number.

1211431422413 is a deficient number, since it is larger than the sum of its proper divisors (275894035).

1211431422413 is an equidigital number, since it uses as much as digits as its factorization.

1211431422413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 275894034.

The product of its digits is 4608, while the sum is 29.

Adding to 1211431422413 its reverse (3142241341121), we get a palindrome (4353672763534).

The spelling of 1211431422413 in words is "one trillion, two hundred eleven billion, four hundred thirty-one million, four hundred twenty-two thousand, four hundred thirteen".