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12114332003 = 57121215993
BaseRepresentation
bin10110100100001001…
…00000100101100011
31011021021020211101002
423102010200211203
5144302232111003
65322032102215
7606130060124
oct132204404543
934237224332
1012114332003
115157251a34
12242109496b
1311b0a558b7
1482cca004b
154ad806a88
hex2d2120963

12114332003 has 4 divisors (see below), whose sum is σ = 12135548568. Its totient is φ = 12093115440.

The previous prime is 12114331979. The next prime is 12114332011. The reversal of 12114332003 is 30023341121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12114332003 - 26 = 12114331939 is a prime.

It is a super-3 number, since 3×121143320033 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12114332903) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10607426 + ... + 10608567.

It is an arithmetic number, because the mean of its divisors is an integer number (3033887142).

Almost surely, 212114332003 is an apocalyptic number.

12114332003 is a deficient number, since it is larger than the sum of its proper divisors (21216565).

12114332003 is an equidigital number, since it uses as much as digits as its factorization.

12114332003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21216564.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 12114332003 its reverse (30023341121), we get a palindrome (42137673124).

The spelling of 12114332003 in words is "twelve billion, one hundred fourteen million, three hundred thirty-two thousand, three".

Divisors: 1 571 21215993 12114332003