12114341255453 has 2 divisors, whose sum is σ = 12114341255454. Its totient is φ = 12114341255452.

The previous prime is 12114341255447. The next prime is 12114341255473. The reversal of 12114341255453 is 35455214341121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11237097343684 + 877243911769 = 3352178^2 + 936613^2 .

It is an emirp because it is prime and its reverse (35455214341121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12114341255453 - 2²⁴ = 12114324478237 is a prime.

It is a super-3 number, since 3×12114341255453³ (a number of 40 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12114341255453.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12114341255473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6057170627726 + 6057170627727.

It is an arithmetic number, because the mean of its divisors is an integer number (6057170627727).

Almost surely, 2^{12114341255453} is an apocalyptic number.

It is an amenable number.

12114341255453 is a deficient number, since it is larger than the sum of its proper divisors (1).

12114341255453 is an equidigital number, since it uses as much as digits as its factorization.

12114341255453 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 288000, while the sum is 41.

Adding to 12114341255453 its reverse (35455214341121), we get a palindrome (47569555596574).

The spelling of 12114341255453 in words is "twelve trillion, one hundred fourteen billion, three hundred forty-one million, two hundred fifty-five thousand, four hundred fifty-three".