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12114400210013 is a prime number
BaseRepresentation
bin1011000001001001101010…
…0001010110110001011101
31120220010101101020220112202
42300102122201112301131
53041440242423210023
641433140103341245
72360144062524413
oct260223241266135
946803341226482
1012114400210013
113950763107912
121437a28151825
1369b4c96c424a
142dc4a93332b3
151601cb494128
hexb049a856c5d

12114400210013 has 2 divisors, whose sum is σ = 12114400210014. Its totient is φ = 12114400210012.

The previous prime is 12114400210001. The next prime is 12114400210043. The reversal of 12114400210013 is 31001200441121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12094132986244 + 20267223769 = 3477662^2 + 142363^2 .

It is a cyclic number.

It is not a de Polignac number, because 12114400210013 - 24 = 12114400209997 is a prime.

It is a super-3 number, since 3×121144002100133 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12114400210043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6057200105006 + 6057200105007.

It is an arithmetic number, because the mean of its divisors is an integer number (6057200105007).

Almost surely, 212114400210013 is an apocalyptic number.

It is an amenable number.

12114400210013 is a deficient number, since it is larger than the sum of its proper divisors (1).

12114400210013 is an equidigital number, since it uses as much as digits as its factorization.

12114400210013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 12114400210013 its reverse (31001200441121), we get a palindrome (43115600651134).

The spelling of 12114400210013 in words is "twelve trillion, one hundred fourteen billion, four hundred million, two hundred ten thousand, thirteen".