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12114413413 is a prime number
BaseRepresentation
bin10110100100001001…
…10100011101100101
31011021021101222001021
423102010310131211
5144302242212123
65322033531141
7606130546354
oct132204643545
934237358037
1012114413413
1151572a8113
122421113ab1
1311b0a8397b
1482ccc199b
154ad820c5d
hex2d2134765

12114413413 has 2 divisors, whose sum is σ = 12114413414. Its totient is φ = 12114413412.

The previous prime is 12114413407. The next prime is 12114413431. The reversal of 12114413413 is 31431441121.

Together with next prime (12114413431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11934907009 + 179506404 = 109247^2 + 13398^2 .

It is a cyclic number.

It is not a de Polignac number, because 12114413413 - 213 = 12114405221 is a prime.

It is a super-3 number, since 3×121144134133 (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12114413473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6057206706 + 6057206707.

It is an arithmetic number, because the mean of its divisors is an integer number (6057206707).

Almost surely, 212114413413 is an apocalyptic number.

It is an amenable number.

12114413413 is a deficient number, since it is larger than the sum of its proper divisors (1).

12114413413 is an equidigital number, since it uses as much as digits as its factorization.

12114413413 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1152, while the sum is 25.

Adding to 12114413413 its reverse (31431441121), we get a palindrome (43545854534).

The spelling of 12114413413 in words is "twelve billion, one hundred fourteen million, four hundred thirteen thousand, four hundred thirteen".