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12115031553193 is a prime number
BaseRepresentation
bin1011000001001100000000…
…1001101111010010101001
31120220012000101020110120111
42300103000021233102221
53041443041034200233
641433322455254321
72360165530045162
oct260230011572251
946805011213514
1012115031553193
113950a57523338
121437b8367a3a1
1369b59a4452aa
142dc529118769
15160216b03acd
hexb04c026f4a9

12115031553193 has 2 divisors, whose sum is σ = 12115031553194. Its totient is φ = 12115031553192.

The previous prime is 12115031553137. The next prime is 12115031553203. The reversal of 12115031553193 is 39135513051121.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7895470572544 + 4219560980649 = 2809888^2 + 2054157^2 .

It is a cyclic number.

It is not a de Polignac number, because 12115031553193 - 229 = 12114494682281 is a prime.

It is not a weakly prime, because it can be changed into another prime (12115031553133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6057515776596 + 6057515776597.

It is an arithmetic number, because the mean of its divisors is an integer number (6057515776597).

Almost surely, 212115031553193 is an apocalyptic number.

It is an amenable number.

12115031553193 is a deficient number, since it is larger than the sum of its proper divisors (1).

12115031553193 is an equidigital number, since it uses as much as digits as its factorization.

12115031553193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60750, while the sum is 40.

The spelling of 12115031553193 in words is "twelve trillion, one hundred fifteen billion, thirty-one million, five hundred fifty-three thousand, one hundred ninety-three".