Base | Representation |
---|---|
bin | 1011000001001100001101… |
… | …1111111110010101110101 |
3 | 1120220012011021220201020112 |
4 | 2300103003133332111311 |
5 | 3041443144423314103 |
6 | 41433332223112405 |
7 | 2360200111311251 |
oct | 260230337762565 |
9 | 46805137821215 |
10 | 12115087713653 |
11 | 3950a861a1541 |
12 | 1437b9a442705 |
13 | 69b5a8c79732 |
14 | 2dc532777261 |
15 | 16021b9e8cd8 |
hex | b04c37fe575 |
12115087713653 has 2 divisors, whose sum is σ = 12115087713654. Its totient is φ = 12115087713652.
The previous prime is 12115087713649. The next prime is 12115087713779. The reversal of 12115087713653 is 35631778051121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12073838916049 + 41248797604 = 3474743^2 + 203098^2 .
It is a cyclic number.
It is not a de Polignac number, because 12115087713653 - 22 = 12115087713649 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12115087713353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6057543856826 + 6057543856827.
It is an arithmetic number, because the mean of its divisors is an integer number (6057543856827).
Almost surely, 212115087713653 is an apocalyptic number.
It is an amenable number.
12115087713653 is a deficient number, since it is larger than the sum of its proper divisors (1).
12115087713653 is an equidigital number, since it uses as much as digits as its factorization.
12115087713653 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1058400, while the sum is 50.
The spelling of 12115087713653 in words is "twelve trillion, one hundred fifteen billion, eighty-seven million, seven hundred thirteen thousand, six hundred fifty-three".
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